Answer
$g’(t)=-6t^{-3}e^{-3t^{-2}}$
Work Step by Step
$g(t)=e^{-3t^{-2}}$
let
u=$-3t^{-2}$
u'=$-6t^{-3}$
$g(u)=e^u$
$g'(u)=u'e^u$
$g’(t)=-6t^{-3}e^{-3t^{-2}}$
Calculus 10th Edition
by Larson, Ron; Edwards, Bruce H.
Published by
Brooks Cole
ISBN 10:
1-28505-709-0
ISBN 13:
978-1-28505-709-5
Chapter 5 - Logarithmic, Exponential, and Other Transcendental Functions - 5.4 Exercises - Page 352: 44
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