Calculus, 10th Edition (Anton)

Published by Wiley
ISBN 10: 0-47064-772-8
ISBN 13: 978-0-47064-772-1

Chapter 7 - Principles Of Integral Evaluation - 7.8 Improper Integrals - Exercises Set 7.8 - Page 554: 28

Answer

$$3$$

Work Step by Step

Simplify the improper integral $\int_{0}^{1} \dfrac{1}{(x-1)^{2/3}} dx$ Let us consider that $I=\int_{0}^{1} \dfrac{1}{(x-1)^{2/3}} dx$ Plug $a=x-1 \implies da=dx$ Integrate the integral by using limits. $I=\int_0^1 \dfrac{1}{a^{2/3}} da \\=|3a^{1/3}|_0^1\\=|3 \sqrt[3]{x-1}|_0^1 \\=0-(-3) \\=3$
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