Calculus, 10th Edition (Anton)

Published by Wiley
ISBN 10: 0-47064-772-8
ISBN 13: 978-0-47064-772-1

Chapter 13 - Partial Derivatives - 13.2 Limits And Continuity - Exercises Set 13.2 - Page 925: 10

Answer

0

Work Step by Step

We find: \[ \lim _{(x, y) \rightarrow(0,0)} \frac{1-\cos \left(x^{2}+y^{2}\right)}{x^{2}+y^{2}} \] Given that if $(x, y) \rightarrow(0,0)$ then $z \rightarrow 0$, so we re-write the equation: \[ \begin{array}{l} =\lim _{z \rightarrow 0} \frac{1-\cos z}{z} * \frac{(1+\cos z)}{1+\cos z} \\ =\lim _{z \rightarrow 0} \frac{1-\cos ^{2} z}{z}(1+\cos z) \\ =\lim _{z \rightarrow 0} \frac{\sin z}{z} \frac{\sin z}{(1+\cos z)} \\ =1 * 0 \\ =0 \end{array} \]
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