Answer
$\frac{m^3-4m^2-8 m+50}{m-4}=m^2-8+\frac{18}{m-4}$
Work Step by Step
Given \begin{equation}
\begin{aligned}
\left(m^3-4m^2-8 m+50\right) \div(m-4).
\end{aligned}
\end{equation} Use synthetic division. \begin{equation}
\begin{array}{r|rrrr}
4&1 & -4 & -8& 50 \\
& & 4 & 0& -32 \\
\hline & 1 & 0 & -8& 18
\end{array}
\end{equation} The solution is \begin{equation}
\begin{aligned}
\frac{m^3-4m^2-8 m+50}{m-4}=m^2-8+\frac{18}{m-4}.
\end{aligned}
\end{equation}