Answer
$2x^2+3x+5$
Work Step by Step
Given \begin{equation}
\begin{aligned}
\left(2 x^3+11 x^2+17 x+20\right) \div(x+4)
\end{aligned}
\end{equation} Use synthetic division. \begin{equation}
\begin{array}{r|rrrr}
-4&2 & 11 & 17& 20 \\
& & -8 & -12& -20 \\
\hline & 2 & 3 & 5& 0
\end{array}
\end{equation} The solution is \begin{equation}
\begin{aligned}
\frac{2 x^3+11 x^2+17 x+20}{x+4}= 2x^2+3x+5
\end{aligned}
\end{equation}
