Answer
$x+4$
Work Step by Step
Given \begin{equation}
\begin{aligned}
\left(x^2-3 x-28\right) \div(x-7)
\end{aligned}
\end{equation} \pi\piUse synthetic division.
\begin{equation}
\begin{array}{r|rrr}
7& 1 & -3 & -28 \\
& & 7 & 28 \\
\hline & 1 & 4 & 0
\end{array}
\end{equation} The solution is \begin{equation}
\begin{aligned}
\frac{x^2-3 x-28}{x-7}= x+4
\end{aligned}
\end{equation}