Answer
The solutions are $x=\pm2$
Work Step by Step
$4x^{2}-16=0$
Take $16$ to the right side:
$4x^{2}=16$
Take the $4$ to divide the right side:
$x^{2}=\dfrac{16}{4}$
$x^{2}=4$
Take the square root of both sides of the equation:
$\sqrt{x^{2}}=\pm\sqrt{4}$
$x=\pm2$
