## College Algebra (6th Edition)

The solutions are $x=2$ and $x=\dfrac{1}{5}$
$5x^{2}+2=11x$ Take $11x$ to the left side: $5x^{2}-11x+2=0$ Solve this equation by factoring: $(5x-1)(x-2)=0$ Set both factors equal to $0$ and solve each individual equation for $x$: $5x-1=0$ $5x=1$ $x=\dfrac{1}{5}$ $x-2=0$ $x=2$ The solutions are $x=2$ and $x=\dfrac{1}{5}$