## College Algebra (6th Edition)

The solutions are $x=0$ and $x=\dfrac{7}{2}$
$2x^{2}-7x=0$ Take out common factor $x$ from the left side: $x(2x-7)=0$ Set both factors equal to $0$ and solve each individual equation for $x$: $x=0$ $2x-7=0$ $2x=7$ $x=\dfrac{7}{2}$ The solutions are $x=0$ and $x=\dfrac{7}{2}$