College Algebra (6th Edition)

$x=\frac{-5-\sqrt {13}}{2},\frac{-5+\sqrt {13}}{2}$
Plug the values $a$, $b$, and $c$ into the quadratic formula and simplify all the values. $x^2+5x+3=0$ $a=1,b=5,c=3$ $x=\frac{-b±\sqrt {b^2-4ac}}{2a}$ $x=\frac{-5±\sqrt {5^2-4(1)(3)}}{2(1)}$ $x=\frac{-5±\sqrt {25-12}}{2}$ $x=\frac{-5±\sqrt {13}}{2}$ $x=\frac{-5-\sqrt {13}}{2},\frac{-5+\sqrt {13}}{2}$