Answer
$x=\frac{-5-\sqrt {13}}{2},\frac{-5+\sqrt {13}}{2}$
Work Step by Step
Plug the values $a$, $b$, and $c$ into the quadratic formula and simplify all the values.
$x^2+5x+3=0$
$a=1,b=5,c=3$
$x=\frac{-b±\sqrt {b^2-4ac}}{2a}$
$x=\frac{-5±\sqrt {5^2-4(1)(3)}}{2(1)}$
$x=\frac{-5±\sqrt {25-12}}{2}$
$x=\frac{-5±\sqrt {13}}{2}$
$x=\frac{-5-\sqrt {13}}{2},\frac{-5+\sqrt {13}}{2}$
