Answer
$x=-1$ and $x=\dfrac{2}{5}$ satisfy the given conditions
Work Step by Step
$y=5x^{2}+3x$ and $y=2$
Substitute $y$ by $2$:
$2=5x^{2}+3x$
Take the $2$ to the right side of the equation:
$0=5x^{2}+3x-2$
Rearrange:
$5x^{2}+3x-2=0$
Solve by factoring:
$(x+1)(5x-2)=0$
Set both factors equal to $0$ and solve each individual equation for $x$:
$x+1=0$
$x=-1$
$5x-2=0$
$5x=2$
$x=\dfrac{2}{5}$
$x=-1$ and $x=\dfrac{2}{5}$ satisfy the given conditions
