Answer
Discriminant = 40; 2 unequal real solutions that are irrational
Work Step by Step
$3x^2+4x-2=0$
Plug the coefficients into the discriminant of the quadratic formula.
$a=3, b=4, c=-2$
$\sqrt {b^2-4ac}$
$\sqrt {(4)^2-4(3)(-2)}$
$\sqrt {16+24}$
$\sqrt {40}$
Since the discriminant is greater than $0$, the equation has two unequal real solutions that are irrational.