Answer
The solutions are $x=-3$ and $x=\dfrac{1}{2}$
Work Step by Step
$2x^{2}+5x=3$
Take the $3$ to the left side of the equation:
$2x^{2}+5x-3=0$
Solve this equation by factoring:
$(x+3)(2x-1)=0$
Set both factors equal to $0$ and solve each individual equation for $x$:
$x+3=0$
$x=-3$
$2x-1=0$
$2x=1$
$x=\dfrac{1}{2}$
The solutions are $x=-3$ and $x=\dfrac{1}{2}$
