College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 1 - Equations and Inequalities - Exercise Set 1.5 - Page 161: 69


$x=\frac{3-\sqrt {57}}{6},\frac{3+\sqrt {57}}{6}$

Work Step by Step

Plug the values $a$, $b$, and $c$ into the quadratic formula and simplify all the values. $3x^2-3x=4=0$ $a=3,b=-3,c=-4$ $x=\frac{-b±\sqrt {b^2-4ac}}{2a}$ $x=\frac{-(-3)±\sqrt {(-3)^2-4(3)(-4)}}{2(3)}$ $x=\frac{3±\sqrt {9+48}}{6}$ $x=\frac{3±\sqrt {57}}{6}$ $x=\frac{3-\sqrt {57}}{6},\frac{3+\sqrt {57}}{6}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.