College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 1 - Equations and Inequalities - Exercise Set 1.5 - Page 161: 84


The solutions are $x=-\dfrac{2}{3}$ and $x=2$

Work Step by Step

$3x^{2}-4x=4$ Take the $4$ to the left side: $3x^{2}-4x-4=0$ Solve this equation by factoring: $(3x+2)(x-2)=0$ Set both factors equal to $0$ and solve both individual equations for $x$: $3x+2=0$ $3x=-2$ $x=-\dfrac{2}{3}$ $x-2=0$ $x=2$ The solutions are $x=-\dfrac{2}{3}$ and $x=2$
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