Answer
The solution is $x=2$
Work Step by Step
$3x^{2}-12x+12=0$
Take out common factor $3$ from the left side:
$3(x^{2}-4x+4)=0$
Take the $3$ to divide the right side:
$x^{2}-4x+4=\dfrac{0}{4}$
$x^{2}-4x+4=0$
Solve this equation by factoring:
$(x-2)^{2}=0$
Take the square root of both sides:
$\sqrt{(x-2)^{2}}=\sqrt{0}$
$x-2=0$
Solve for $x$:
$x=2$
