Answer
$x=\frac{-1-\sqrt {41}}{10},\frac{-1+\sqrt {41}}{10}$
Work Step by Step
Plug the values $a$, $b$, and $c$ into the quadratic formula and simplify all the values.
$5x^2+x-2=0$
$a=5,b=1,c=-2$
$x=\frac{-b±\sqrt {b^2-4ac}}{2a}$
$x=\frac{-1±\sqrt {1^2-4(5)(-2)}}{2(5)}$
$x=\frac{-1±\sqrt {1+40}}{10}$
$x=\frac{-1±\sqrt {41}}{10}$
$x=\frac{-1-\sqrt {41}}{10},\frac{-1+\sqrt {41}}{10}$
