College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 1 - Equations and Inequalities - Exercise Set 1.5 - Page 161: 86

Answer

The solutions are $x=-3$ and $x=\dfrac{2}{5}$

Work Step by Step

$5x^{2}=6-13x$ Take all terms to the left side of the equation: $5x^{2}+13x-6=0$ Solve this equation by factoring: $(x+3)(5x-2)=0$ Set both factors equal to $0$ and solve each individual equation for $x$: $x+3=0$ $x=-3$ $5x-2=0$ $5x=2$ $x=\dfrac{2}{5}$ The solutions are $x=-3$ and $x=\dfrac{2}{5}$
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