Answer
$x=\frac{1-\sqrt {29}}{4},\frac{1+\sqrt {29}}{4}$
Work Step by Step
Plug the values $a$, $b$, and $c$ into the quadratic formula and simplify all the values.
$4x^2=2x+7$
$4x^2-2x-7=0$
$a=4,b=-2,c=-7$
$x=\frac{-b±\sqrt {b^2-4ac}}{2a}$
$x=\frac{-(-2)±\sqrt {(-2)^2-4(4)(-7)}}{2(4)}$
$x=\frac{2±\sqrt {4+112}}{8}$
$x=\frac{2±\sqrt {116}}{8}$
$x=\frac{2±2\sqrt {29}}{8}$
$x=\frac{1±\sqrt {29}}{4}$
$x=\frac{1-\sqrt {29}}{4},\frac{1+\sqrt {29}}{4}$
