Answer
Discriminant = 36; 2 unequal real solutions
Work Step by Step
$x^2-4x-5=0$
Plug the coefficients into the discriminant of the quadratic formula.
$a=1, b=-4, c=-5$
$\sqrt {b^2-4ac}$
$\sqrt {(-4)^2-4(1)(-5)}$
$\sqrt {16+20}$
$\sqrt {36}$
Since the discriminant is greater than $0$, the equation has two unequal real solutions.