College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 1 - Equations and Inequalities - Exercise Set 1.5 - Page 161: 83

Answer

x=1 or -$\frac{1}{2}$

Work Step by Step

2x$^2$-x=1 x$^2$-$\frac{1}{2}$x=$\frac{1}{2}$ (x-$\frac{1}{4}$)$^2$=$\frac{9}{16}$ x-$\frac{1}{4}$= +/-$\frac{3}{4}$ x=1 or -$\frac{1}{2}$
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