Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter P - Review Exercises: 99

Answer

$(y – 2)(y^2 + 2y + 4)$

Work Step by Step

Recall that $a^3 – b^3 = (a – b)(a^2 + ab + b^2)$. $y^3-8=y^3-2^3$ We use this to simplify the expression: $y^3-8=(y – 2)(y^2 + 2y + 2^2)$.
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