## Precalculus (6th Edition) Blitzer

$(y – 2)(y^2 + 2y + 4)$
Recall that $a^3 – b^3 = (a – b)(a^2 + ab + b^2)$. $y^3-8=y^3-2^3$ We use this to simplify the expression: $y^3-8=(y – 2)(y^2 + 2y + 2^2)$.