## Precalculus (6th Edition) Blitzer

Published by Pearson

# Chapter P - Review Exercises - Page 143: 99

#### Answer

$(y – 2)(y^2 + 2y + 4)$

#### Work Step by Step

Recall that $a^3 – b^3 = (a – b)(a^2 + ab + b^2)$. $y^3-8=y^3-2^3$ We use this to simplify the expression: $y^3-8=(y – 2)(y^2 + 2y + 2^2)$.

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.