Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter P - Review Exercises - Page 143: 63

Answer

$4$

Work Step by Step

Recall that $a^{x/y}=\sqrt[y] {a^x}$. Thus, $16^{1/2}=\sqrt {16}=4$.
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