Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter P - Review Exercises - Page 143: 53


$7\sqrt 7+7\sqrt 5$

Work Step by Step

$\frac{14}{\sqrt 7-\sqrt 5}=\frac{14(\sqrt 7+\sqrt 5)}{(\sqrt 7-\sqrt 5)(\sqrt 7+\sqrt 5)}=\frac{14(\sqrt 7+\sqrt 5)}{7-5}=\frac{14(\sqrt 7+\sqrt 5)}{2}=7(\sqrt 7+\sqrt 5)=7\sqrt 7+7\sqrt 5$
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