## Precalculus (6th Edition) Blitzer

$x^2$, with $x=-2$ excluded from the domain
$\frac{x^3+2x^2}{x+2}=\frac{x^2(x+2)}{x+2}=x^2$ $x=-2$ must be excluded from the domain, because $(-2)+2=0$ and you can't have a denominator that equals zero.