Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter P - Review Exercises - Page 143: 109


$x^2$, with $x=-2$ excluded from the domain

Work Step by Step

$\frac{x^3+2x^2}{x+2}=\frac{x^2(x+2)}{x+2}=x^2$ $x=-2$ must be excluded from the domain, because $(-2)+2=0$ and you can't have a denominator that equals zero.
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