Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter P - Review Exercises - Page 143: 75



Work Step by Step

$(3x-2)(4x^2+3x-5)= (3x)(4x^2)+(3x)(3x)+(3x)(-5)+(-2)(4x^2)+(-2)(3x)+(-2)(-5)= 12x^3+9x^2-15x-8x^2-6x+10=12x^3+x^2-21x+10$
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