Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter P - Review Exercises - Page 143: 51


$\frac{\sqrt 6}{3}$

Work Step by Step

$\frac{\sqrt 2}{\sqrt 3}=\frac{\sqrt 2\sqrt 3}{\sqrt 3\sqrt 3}=\frac{\sqrt {2\times3}}{3}=\frac{\sqrt 6}{3}$
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