Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter P - Review Exercises: 68

Answer

$\frac{1}{81}$

Work Step by Step

$27^{-\frac{4}{3}}=\frac{1}{\sqrt[3] {27}^4}=\frac{1}{3^4}=\frac{1}{81}$
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