Answer
$\displaystyle \frac{16(1+2x)}{x^{3/4}}$
Work Step by Step
We keep in mind the simplification:
$ x^{1/4}=x^{1-3/4}=x\cdot x^{-3x}$
We start by factoring out $16x^{-3/4}$
$16x^{-3/4}+32x^{1/4}=16x^{-3/4}(1+2x)$
To have all positive exponents, we rewrite as:
= $\displaystyle \frac{16(1+2x)}{x^{3/4}}$
