Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter P - Review Exercises - Page 143: 110


$\frac{x-3}{x-6}$, $x\ne\pm6$

Work Step by Step

Step 1. The domain requirement of the rational expression is that $x^2-36\ne0$, which gives $x\ne\pm6$ Step 2. Factor the numerator and the denominator completely. We have $\frac{x^2+3x-18}{x^2-36}=\frac{(x+6)(x-3)}{(x+6)(x-6)}$ Step 3. Cancel the common factors from the above expression. We get the result as $\frac{x-3}{x-6}$ with $x\ne\pm6$
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