Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter P - Review Exercises - Page 143: 96

Answer

$(x-3)^{2}(x+3)$

Work Step by Step

Factor in pairs, $ x^{2}$ from the first two, $-3$ from the other pair. $=x^{2}(x-3)-9(x-3)$ $=(x-3)(x^{2}-9)$ We recognize a difference of squares: $=(x-3)\cdot(x-3)(x+3)$ $=(x-3)^{2}(x+3)$
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