Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter P - Review Exercises - Page 143: 60



Work Step by Step

$\sqrt[4]{8}\cdot \sqrt[4]{10}=\qquad $... apply $\sqrt[n]{a\cdot b}$ = $\sqrt[n]{a}\cdot \sqrt[n]{b}$ $=\sqrt[4]{8\cdot 10}=\sqrt[4]{2^{3}\cdot 2\cdot 5}$ $=\sqrt[4]{2^{4}\cdot 5}$ $= \sqrt[4]{2^{4}}\cdot \sqrt[4]{5}$ Apply $\qquad \sqrt[n]{y^{n}}=|y|,\qquad $ when n is even. = $2\sqrt[4]{5}$
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