## Precalculus (6th Edition) Blitzer

$2\sqrt[4]{5}$
$\sqrt[4]{8}\cdot \sqrt[4]{10}=\qquad$... apply $\sqrt[n]{a\cdot b}$ = $\sqrt[n]{a}\cdot \sqrt[n]{b}$ $=\sqrt[4]{8\cdot 10}=\sqrt[4]{2^{3}\cdot 2\cdot 5}$ $=\sqrt[4]{2^{4}\cdot 5}$ $= \sqrt[4]{2^{4}}\cdot \sqrt[4]{5}$ Apply $\qquad \sqrt[n]{y^{n}}=|y|,\qquad$ when n is even. = $2\sqrt[4]{5}$