Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter P - Review Exercises - Page 143: 91

Answer

$(5x-2)(3x+1)$

Work Step by Step

Factoring $ ax^{2}+bx+c $, we search for factors of $ ac $ whose sum is $ b.$ If they exist, we rewrite $ bx $ and factor in pairs. We see that $-6$ and $5$ are factors of $15(-2)=-30$, and their sum is $-1.$ $15x^{2}-x-2=15x^{2}-6x+5x-2$ $=3x(5x-2)+(5x-2)$ $=(5x-2)(3x+1)$
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