Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter P - Review Exercises - Page 143: 100

Answer

$(x + 4)(x^2 - 4x + 16)$.

Work Step by Step

Recall that $a^3 + b^3 = (a + b)(a^2 - ab + b^2)$. $x^3+64=x^3+4^3$ We use this to simplify the expression: $x^3+64=(x + 4)(x^2 - 4x + 4^2)$.
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