Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter P - Review Exercises - Page 143: 88

Answer

$ a^{3}-b^{3}$

Work Step by Step

Distribute $(a-b)(a^{2}+ab+b^{2})=a(a^{2}+ab+b^{2})-b(a^{2}+ab+b^{2})$ $=a^{3}+a^{2}b+ab^{2}-a^{2}b-ab^{2}-b^{3}$ The terms $ a^{2}b $ and $ ab^{2}$ cancel = $ a^{3}-b^{3}$
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