Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter P - Review Exercises - Page 143: 94



Work Step by Step

Factor out $3x^{2}$ $=3x^{2}(x^{2}-3x-10)$ Factoring $ x^{2}+bx+c $, we search for factors (m and n) of $ c $ whose sum is $ b.$ If they (m and n) exist, we obtain $(x+m)(x+n)$. We see that $-5$ and $+2$ are factors of $-10$, and their sum is $-3.$ = $3x^2(x+2)(x-5)$
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