Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter P - Review Exercises: 46

Answer

$4x\sqrt 3$

Work Step by Step

$\frac{\sqrt {96x^3}}{\sqrt {2x}}=\sqrt \frac{96x^3}{2x}=\sqrt {48x^2}=\sqrt {48}\times\sqrt {x^2}=\sqrt {(16\times3)} \times x=\sqrt {16}\times\sqrt 3\times x=4\times\sqrt 3\times x= 4x\sqrt 3$
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