Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter P - Review Exercises - Page 143: 119

Answer

$\frac{3}{x}$, $x\ne0, 2$

Work Step by Step

Step 1. To remove the fractions, we can multiply both the numerator and the denominator with a common factor $6x$. Step 2. We have $\frac{\frac{1}{x}-\frac{1}{2}}{\frac{1}{3}-\frac{x}{6}}\cdot \frac{6x}{6x}=\frac{6-3x}{2x-x^2}=\frac{3(2-x)}{x(2-x)}$ Step 3. Provided that $x\ne0, 2$, simplify the above result. We get $\frac{3}{x}$ Step 4. We conclude the result as $\frac{3}{x}$, with $x\ne0, 2$
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