Answer
$6$.
Work Step by Step
The given expression is
$=\sqrt{36}$
Use $36=6^2$
$=\sqrt{6^2}$
The principal square root is nonnegative.
The absolute value is
$=6$.
Precalculus (10th Edition)
by Sullivan, Michael
Published by
Pearson
ISBN 10:
0-32197-907-9
ISBN 13:
978-0-32197-907-0
Appendix A - Review - A.1 Algebra Essentials - A.1 Assess Your Understanding - Page A12: 94
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