Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Appendix A - Review - A.1 Algebra Essentials - A.1 Assess Your Understanding - Page A12: 120

Answer

$44$.

Work Step by Step

The given expression is $=4x^3+3x^2-x+2$ Substitute $x=1$. $=4(1)^3+3(1)^2-(1)+2$ Use $1^3=1$ and $1^2=1$. $=4\cdot 1+3\cdot 1-1+2$ Simplify. $=4+3-1+2$ $=8$. Substitute $x=2$. $=4(2)^3+3(2)^2-(2)+2$ Use $2^3=8$ and $2^2=4$. $=4\cdot 8+3\cdot 4-2+2$ Simplify. $=32+12-2+2$ $=44$.
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