Answer
$\frac{1}{x^3y}$.
Work Step by Step
The given expression is
$=\frac{x^{-2}y}{xy^2}$
Or we can write.
$=\frac{x^{-2}}{x^1}\cdot \frac{y^{1}}{y^2}$
Use the law of exponents $\frac{a^{m}}{a^n}=a^{m-n}$
$=(x^{-2-1})\cdot (y^{1-2})$
Simplify.
$=(x^{-3})\cdot (y^{-1})$
Use the law of exponents $a^{-n}=\frac{1}{a^{n}}$
$=\frac{1}{x^3}\cdot \frac{1}{y}$
$=\frac{1}{x^3y}$.
