Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Appendix A - Review - A.1 Algebra Essentials - A.1 Assess Your Understanding - Page A12: 81

Answer

$0^{\circ}C$.

Work Step by Step

The given formula is $\Rightarrow C=\frac{5}{9}(F-32)$ Substitute $F=32^{\circ}$. $\Rightarrow C=\frac{5}{9}(32-32)$ Simplify. $\Rightarrow C=\frac{5}{9}(0)$ $\Rightarrow C=0$ Hence, the temperature is $0^{\circ}C$.
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