Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Appendix A - Review - A.1 Algebra Essentials - A.1 Assess Your Understanding - Page A12: 83

Answer

$25^{\circ}C$.

Work Step by Step

The given formula is $\Rightarrow C=\frac{5}{9}(F-32)$ Substitute $F=77^{\circ}$. $\Rightarrow C=\frac{5}{9}(77-32)$ Simplify. $\Rightarrow C=\frac{5}{9}(45)$ $\Rightarrow C=25$ Hence, the temperature is $25^{\circ}C$.
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