Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Appendix A - Review - A.1 Algebra Essentials - A.1 Assess Your Understanding - Page A12: 71

Answer

$(a)\; x=3$.

Work Step by Step

The given expression is $=\frac{x}{x^2-9} $ (a) Substitute $x=3$. $=\frac{3}{3^2-9} $ Simplify. $=\frac{3}{9-9} $ $=\frac{3}{0} $ Not defined. (b) Substitute $x=1$. $=\frac{1}{1^2-9} $ Simplify. $=\frac{1}{1-9} $ $=\frac{1}{-8} $ $=-\frac{1}{8} $ (c) Substitute $x=0$. $=\frac{0}{0^2-9} $ Simplify. $=\frac{0}{0-9} $ $=\frac{0}{-9} $ $=0 $ (d) Substitute $x=-1$. $=\frac{-1}{(-1)^2-9} $ Simplify. $=\frac{-1}{1-9} $ $=\frac{-1}{-8} $ $=\frac{1}{8} $ Hence, the correct answer is $(a)\; x=3$.
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