Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Appendix A - Review - A.1 Algebra Essentials - A.1 Assess Your Understanding - Page A12: 112

Answer

$=1$.

Work Step by Step

The given expression is $=(x+y)^2$ Substitute $x=2$ and $y=-1$. $=(2+ (-1))^2$ Clear inner parentheses $=(2-1)^2$ Use the law of exponents $(a)^{n}=a^{n}$ $=1^2$ Use $1^2=1$ $=1$.
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