Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Appendix A - Review - A.1 Algebra Essentials - A.1 Assess Your Understanding - Page A12: 91

Answer

$9$.

Work Step by Step

The given expression is $=(3^{-2})^{-1}$ Use the law of exponents $(a^{m})^n=a^{mn}$ We have $a=3,m=-2$ and $n=-1$ $=3^{(-2)(-1)}$ Simplify. $=3^{2}$ Use $3^2=9$ $=9$.
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