Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Appendix A - Review - A.1 Algebra Essentials - A.1 Assess Your Understanding - Page A12: 101

Answer

$\frac{x}{y}$.

Work Step by Step

The given expression is $=\frac{x^{2}y^{3}}{xy^4}$ Or we can write. $=\frac{x^{2}}{x^1}\cdot \frac{y^{3}}{y^4}$ Use the law of exponents $\frac{a^{m}}{a^n}=a^{m-n}$ $=(x^{2-1})\cdot (y^{3-4})$ Simplify. $=(x^{1})\cdot (y^{-1})$ Use the law of exponents $(a)^{-n}=\frac{1}{a^{n}}$ $=x\cdot \frac{1}{y}$ $=\frac{x}{y}$.
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