Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Appendix A - Review - A.1 Algebra Essentials - A.1 Assess Your Understanding - Page A12: 100

Answer

$\frac{y^{3}}{x^3}$.

Work Step by Step

The given expression is $=(x^{-1}y)^{3}$ Use the law of exponents $(ab)^{m}=a^m\cdot b^m$ We have $a=x^{-1}, b=y$ and $m=3$ $=(x^{-1})^3\cdot (y)^{3}$ Use the law of exponents $(a^m)^{n}=a^{m\cdot n}$ $=x^{-1\cdot 3}\cdot y^{3}$ Simplify. $=x^{-3}\cdot y^{3}$. Use the law of exponents $(a)^{-n}=\frac{1}{a^{n}}$ $=\frac{y^{3}}{x^3}$.
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