Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Appendix A - Review - A.1 Algebra Essentials - A.1 Assess Your Understanding - Page A12: 108

Answer

$\frac{3}{2}$.

Work Step by Step

The given expression is $=-3x^{-1}y$ Use the law of exponents $a^{-n}=\frac{1}{a^{n}}$ $=\frac{-3y}{x^{1}}$ Substitute $x=2$ and $y=-1$. $=\frac{-3(-1)}{(2)^{1}}$ Simplify. $=\frac{3}{2}$.
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