Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Appendix A - Review - A.1 Algebra Essentials - A.1 Assess Your Understanding - Page A12: 113

Answer

$2$.

Work Step by Step

The given expression is $=\sqrt{x^2}$ Substitute $x=2$. $=\sqrt{2^2}$ The principal square root is nonnegative. The absolute value is $=2$.
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